expected expression before token как исправить
«Expected expression before ‘ < ' token"
So I keep on running into this issue when I try assigning values to a int array. I read this one expected expression before ‘<' token, but I am still confused on why it is showing up in my code. I have a feeling I am initializing and declaring the array incorrectly and that's why it is giving my issues.
So, before main () I am declaring some group of global variables (yes I know this is dangerous, but required for my purpose). With that group of global variables I also want to declare an double array of size 3
Then in the main function, I am initializing the variables and arrays
However, I am getting the error message «Expected expression before ‘ < ' token" at.
First of all, what does that error message mean? Secondly, is that message coming up because I am initializing and declaring the arrays incorrectly?
4 Answers 4
Best to do the init’ing at declaration time:
Only the arrays need to be done that way, but it’s best to do them all the same way.
Your alternative is
Charlie Burns is correct, it’s always better to initialize the arrays with actual values. However, using the code you supplied, once you declare the array you can only set specific elements:
As you can see, in order to set the variable you use the number inside the brackets corresponding to the element you are trying to set. you cannot set it all at once after declaring the array.
After looking at the answers and comments, I think there are a few more things to clarify:
Then compile & link them:
Q1: What does that error message mean?
Q2: Is that message coming up because I am initializing and declaring the arrays incorrectly?
A2: You are declaring the arrays correctly but not assigning them.
Others have correctly told you the preferred way of doing it.
As an alternative, you could also use compound literal operators introduced with the C99 standard.
Beware, the scope of this array is only inside the function where you assigned it.
Ошибка «expected identifier or ‘(’ before ‘<’ token"
Помогите исправить функцию
Вот такая ошибка: prog.c:25:1: error: expected identifier or ‘(’ before ‘ <’ token
<
^
Помощь в написании контрольных, курсовых и дипломных работ здесь.
Ошибка: «expected constructor, destructor, or type conversion before ‘(‘ token»
connect(CommandLinkButton,clicked(),MainWindow,MainWindow::knopka()); Выдаёт ошибку expected.
Ошибка «expected primary-expression before ‘>’ token»
Задача: Задано линейный массив целых чисел. Увеличить на 2 каждый неотъемлемый элемент массива.
DobroAlex, я не понял куда его вставить можно показать?
Добавлено через 1 час 16 минут
Все равно не работает
volvo, я пробовал, не работает
Вот рабочий код и из него надо сделать функцию
Решение
Помощь в написании контрольных, курсовых и дипломных работ здесь.
Объявление векторов в классе: ошибка «expected identifier before numeric constant»
private: std::vector logins(1); std::vector passwords(1); public: Есть.
USES SysUtils и ошибка Syntax Error, «BEGIN» expected but «identifier SYSUTILS»
Подключаю SysUtils дабы использовать ф-ции StrToInt и IntToStr, но выдает ошибку Fatal: Syntax.
Ошибка: «expected unqualified-id before token ‘(‘ «
Перевожу написанную на x86 linux (ОС МСВС 3.0) в x64 (ОС МСВС 5.0). Вроде как кроссплатформенный.
Expected primary expression before ‘.’
I’m trying to write a simple class program. I am getting the error
6 Answers 6
square is a type, not an object; instead of
(which is implicitly the same as:
which you may, or please may not, prefer for clarity).
2*square::length + 2*square::width would be valid syntax if length and width were
Yes, the accurate form would be:
since square is a type, not an object.
In this context, it’s the same as:
However, since it’s the same object and the same type, you can just write:
You need to say square::perimeter() because you are defining a method of the square class itself. It may seem like you want to define it on a specific object, but you want it to be available to all instances of square, so you need to define it on a specific one.
The instance variables length and width on the other hand, pertain to a specific instance of a class and NOT the entire class itself (otherwise you would declare them as static ). This means that you can just refer to them directly instead of going through the class itself, and the compiler will know what variables you’re talking about. This is because width and length are defined in the same scope as the method, so you don’t need to give it special directions with :: to tell it where to find what its looking for. Hence:
to access instance variables, just name them:
so you perimeter function should be:
But isnt the length and width of square equal?
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